221 lines
4.9 KiB
C++
221 lines
4.9 KiB
C++
#include <cstring>
|
|
#include <ctime>
|
|
#include <cctype>
|
|
|
|
#include "ledger.h"
|
|
|
|
#include <pcre.h> // Perl regular expression library
|
|
|
|
namespace ledger {
|
|
|
|
static char * next_element(char * buf, bool variable = false)
|
|
{
|
|
char * p;
|
|
|
|
if (variable)
|
|
p = std::strstr(buf, " ");
|
|
else
|
|
p = std::strchr(buf, ' ');
|
|
|
|
if (! p)
|
|
return NULL;
|
|
|
|
*p++ = '\0';
|
|
while (std::isspace(*p))
|
|
p++;
|
|
|
|
return p;
|
|
}
|
|
|
|
static int linenum = 0;
|
|
|
|
static inline void finalize_entry(entry * curr)
|
|
{
|
|
if (curr) {
|
|
if (! curr->validate()) {
|
|
std::cerr << "Failed to balance the following transaction, "
|
|
<< "ending on line " << (linenum - 1) << std::endl;
|
|
curr->print(std::cerr);
|
|
} else {
|
|
ledger.push_back(curr);
|
|
}
|
|
}
|
|
}
|
|
|
|
//////////////////////////////////////////////////////////////////////
|
|
//
|
|
// Ledger parser
|
|
//
|
|
|
|
bool parse_ledger(std::istream& in)
|
|
{
|
|
static std::time_t now = std::time(NULL);
|
|
static struct std::tm * now_tm = std::localtime(&now);
|
|
static int current_year = now_tm->tm_year + 1900;
|
|
|
|
static char line[1024];
|
|
|
|
static struct std::tm moment;
|
|
memset(&moment, 0, sizeof(struct std::tm));
|
|
|
|
entry * curr = NULL;
|
|
|
|
// Compile the regular expression used for parsing amounts
|
|
static pcre * entry_re = NULL;
|
|
if (! entry_re) {
|
|
const char *error;
|
|
int erroffset;
|
|
static const std::string regexp =
|
|
"^(([0-9]{4})[./])?([0-9]{2})[./]([0-9]{2})\\s+(\\*\\s+)?"
|
|
"(\\(([^)]+)\\)\\s+)?(.+)";
|
|
entry_re = pcre_compile(regexp.c_str(), 0, &error, &erroffset, NULL);
|
|
}
|
|
|
|
while (! in.eof()) {
|
|
in.getline(line, 1023);
|
|
linenum++;
|
|
|
|
if (in.eof()) {
|
|
break;
|
|
}
|
|
else if (line[0] == '\n') {
|
|
continue;
|
|
}
|
|
else if (std::isdigit(line[0])) {
|
|
static char buf[256];
|
|
int ovector[60];
|
|
|
|
int matched = pcre_exec(entry_re, NULL, line, std::strlen(line),
|
|
0, 0, ovector, 60);
|
|
if (! matched) {
|
|
std::cerr << "Failed to parse, line " << linenum << ": "
|
|
<< line << std::endl;
|
|
continue;
|
|
}
|
|
|
|
if (curr)
|
|
finalize_entry(curr);
|
|
curr = new entry;
|
|
|
|
// Parse the date
|
|
|
|
int mday, mon, year = current_year;
|
|
|
|
if (ovector[1 * 2] >= 0) {
|
|
pcre_copy_substring(line, ovector, matched, 2, buf, 255);
|
|
year = std::atoi(buf);
|
|
}
|
|
|
|
if (ovector[3 * 2] >= 0) {
|
|
pcre_copy_substring(line, ovector, matched, 3, buf, 255);
|
|
mon = std::atoi(buf);
|
|
}
|
|
|
|
if (ovector[4 * 2] >= 0) {
|
|
pcre_copy_substring(line, ovector, matched, 4, buf, 255);
|
|
mday = std::atoi(buf);
|
|
}
|
|
|
|
moment.tm_mday = mday;
|
|
moment.tm_mon = mon - 1;
|
|
moment.tm_year = year - 1900;
|
|
|
|
curr->date = std::mktime(&moment);
|
|
|
|
if (ovector[5 * 2] >= 0)
|
|
curr->cleared = true;
|
|
|
|
if (ovector[6 * 2] >= 0) {
|
|
pcre_copy_substring(line, ovector, matched, 7, buf, 255);
|
|
curr->code = buf;
|
|
}
|
|
|
|
if (ovector[8 * 2] >= 0) {
|
|
int result = pcre_copy_substring(line, ovector, matched, 8, buf, 255);
|
|
assert(result >= 0);
|
|
curr->desc = buf;
|
|
}
|
|
}
|
|
else if (std::isspace(line[0])) {
|
|
transaction * xact = new transaction();
|
|
|
|
char * p = line;
|
|
while (std::isspace(*p))
|
|
p++;
|
|
|
|
// The call to `next_element' will skip past the account name,
|
|
// and return a pointer to the beginning of the amount. Once
|
|
// we know where the amount is, we can strip off any
|
|
// transaction note, and parse it.
|
|
|
|
char * cost_str = next_element(p, true);
|
|
char * note_str;
|
|
|
|
// If there is no amount given, it is intended as an implicit
|
|
// amount; we must use the opposite of the value of the
|
|
// preceding transaction.
|
|
|
|
if (! cost_str || *cost_str == ';') {
|
|
if (cost_str) {
|
|
while (*cost_str == ';' || std::isspace(*cost_str))
|
|
cost_str++;
|
|
xact->note = cost_str;
|
|
}
|
|
xact->cost = curr->xacts.back()->cost->copy();
|
|
xact->cost->negate();
|
|
}
|
|
else {
|
|
note_str = std::strchr(cost_str, ';');
|
|
if (note_str) {
|
|
*note_str++ = '\0';
|
|
while (std::isspace(*note_str))
|
|
note_str++;
|
|
xact->note = note_str;
|
|
}
|
|
|
|
for (char * t = cost_str + (std::strlen(cost_str) - 1);
|
|
std::isspace(*t);
|
|
t--)
|
|
*t = '\0';
|
|
|
|
xact->cost = create_amount(cost_str);
|
|
}
|
|
|
|
account * current = NULL;
|
|
for (char * tok = std::strtok(p, ":");
|
|
tok;
|
|
tok = std::strtok(NULL, ":")) {
|
|
if (! current) {
|
|
accounts_iterator i = accounts.find(tok);
|
|
if (i == accounts.end()) {
|
|
current = new account(tok);
|
|
accounts.insert(accounts_entry(tok, current));
|
|
} else {
|
|
current = (*i).second;
|
|
}
|
|
} else {
|
|
account::iterator i = current->children.find(tok);
|
|
if (i == current->children.end()) {
|
|
current = new account(tok, current);
|
|
current->parent->children.insert(accounts_entry(tok, current));
|
|
} else {
|
|
current = (*i).second;
|
|
}
|
|
}
|
|
}
|
|
xact->acct = current;
|
|
|
|
curr->xacts.push_back(xact);
|
|
}
|
|
else if (line[0] == 'Y') {
|
|
current_year = std::atoi(line + 2);
|
|
}
|
|
}
|
|
|
|
if (curr)
|
|
finalize_entry(curr);
|
|
|
|
return true;
|
|
}
|
|
|
|
} // namespace ledger
|